A chord of a circle of radius 10 cm subtends a right angle at the centre of the circle. Find the area of the corresponding minor segment. [Use $\pi = 3.14$]

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Step 1: Area of minor segment ACB $=$ Area of sector OACB $-$ Area of right $	riangle OAB$
Step 2: Area of sector OACB $= \frac{90}{360} 	imes 3.14 	imes 10 	imes 10 = 78.5$ cm$^2$
Step 3: Area of right $	riangle OAB = \frac{1}{2} 	imes 10 	imes 10 = 50$ cm$^2$
Step 4: Area of minor segment ACB $= 78.5 - 50 = 28.5$ cm$^2$

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