The length of the hour hand of a clock is 10 cm. Find the area of the minor sector swept by the hour hand of the clock between 5 a.m. to 8 a.m. Also, find the area of the major sector.

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Step 1: Central angle subtended by hour hand between 5 am to 8 am $= \frac{360°}{12} 	imes 3 = 90°$
Step 2: Area of minor sector $= \frac{90}{360} 	imes \frac{22}{7} 	imes (10)^2 = \frac{1}{4} 	imes \frac{22}{7} 	imes 100 = \frac{550}{7}$ or $78.57$ cm$^2$ approx.
Step 3: Area of circle $= \frac{22}{7} 	imes (10)^2 = \frac{2200}{7}$ cm$^2$
Step 4: Area of major sector $= \frac{2200}{7} - \frac{550}{7} = \frac{1650}{7}$ or $235.71$ cm$^2$ approx.

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