The perimeter of a certain sector of a circle of radius $5.6$ m is $20.0$ m. Find the area of the sector.

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Step 1: Perimeter of sector $= 2r + \frac{2\pi r 	heta}{360} = 20$
Step 2: $11.2 + 2 	imes \frac{22}{7} 	imes 5.6 	imes \frac{	heta}{360} = 20$
Step 3: Solving, we get $	heta = 90°$
Step 4: Area of sector $= \frac{22}{7} 	imes 5.6 	imes 5.6 	imes \frac{90}{360}$
Step 5: $= 24.64$ m$^2$

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