(ii) (a) What is the total area of parking and the two quadrants?

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Step 1: Area of parking (semi-circle) $= \frac{1}{2} \pi r^2 = \frac{1}{2} 	imes \frac{22}{7} 	imes \left(\frac{7}{2}ight)^2 = \frac{77}{4}$ sq. units
Step 2: Area of 2 quadrants $= 2 	imes \frac{1}{4} \pi r^2 = 2 	imes \frac{22}{7} 	imes 2 	imes 2 	imes \frac{1}{4} = \frac{44}{7}$ sq. units. Total Area $= \frac{77}{4} + \frac{44}{7} = \frac{539 + 176}{28} = \frac{715}{28} = 25.54$ sq. units

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